To test whether to show a dive, the UUIDs of the filtered-by
location and the dive-site of a dive were compared. Since UUIDs
are unique (as the name implies), directly compare pointers.
Note: this code comes from a time when the filtered-by location
was not a pointer, but a copy.
Moreover, the if tested first for the same name, then (logical-or)
for the same uuid. This makes no sense, as the same dive-site
implies the same name. This code likewise can be explained by
historic reasons: the filtered-by location may have contained
a different name. Swap the order of the conditions: first test
for the same object and only of the objects differ, test for
the same same.
Signed-off-by: Berthold Stoeger <bstoeger@mail.tuwien.ac.at>
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